Find all congruences classes x modulo 14 that satisfy the equation 4x ? 10 (mod 14) Because d =gcd(4, 14) = 2 and 2 | 12, we expect there to be d = 2 solutions. To find these we divide through by d = 2: 2x ? 5 (mod 7) 2x ? 12 (mod 7) Since gcd(7, 2) = 1, we can divide by 2. x ? 6 (mod 7) Thus the two solutions modulo 14 are the classes [6] and [6 + 7] = [13]This is a completed example, I just would like an explanation. I get lost at 2|12. Where did 12 come from?
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